September 2018 1 45 Report

\frac{4(3x+2)^{2}}{-9(4-3x)^{2}} = \frac{(16^{4} - 5 \cdot 4^{7}) \cdot 2^{12} }{5 \cdot 32^{5} - 8^{8}}

dla x ≠\frac{4}{3}

prosze o zastosowanie wzorów skróconego mnożenia, i wykonanie zadania, krok po kroku:)


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