Dla jakiej watrości parametru m podana prosta jest równoległa do prostej 3x + 2y - 11 = 0?
a) mx + 6y + 7 =0
b) 3mx + (m² + 1)y - 5 = 0
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2y=-3x-11/:2
y=-3/2x-5,5
wspolczynniki kierunkowe prostych maja byc rowne
a)
6y=-mx+7/:6
y=-m/6x+7/6
-m/6=-3/2
-2m=-18
m=9
b)
y=-3m/(m²+1)x+5/(m²+1)
-3m/(m²+1)= -3/2/:(-3)
m/(m²+1)=1/2
2m=m²+1
m²-2m+1=(m-1)²=0
m=1
3x+2y-11=0
2y=-3x+11
y=-3/2x+5,5
a]
6y=-mx-7
y=-m/6 -7/6
-m/6=-3/2 /*6
-m=-3/2 * 6
-m=-9
m=9
b]
3mx+(m^2+1)y-5=0
(m^2+1)y=-3mx+5 /(m^2+1)
y=-3mx/(m^2+1)+5 (m^2+1)
-3m/(m^2+1)=-3/2 / *(m^2+1)
-3m=-3/2 (m^2+1)
-3m=-3/2m^2-3/2
-3m+3/2m^2=-3/2
3/2m^2-3m+3/2=0
delta=9-4*3/2 * 3/ 2 = 9- 9=0
m=3/(3/2*2)=3/3=1
m=1