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a)
(-1)² + m(-1) -1 =0 ∧ 1²+ mx - 1=0
m=0 ∧ m=0
ostatecznie m=0
b)
(-1)² - mx + 1= 0 ∧ 1² + mx +1 =0
2 - mx = 0 ∧ 2 + mx = 0
m = 2 ∧ m = -2 sprzeczne
m∈Ф ( należy do zbioru pustego)
c)
(-1)² +(m -1)(-1) -m =0 ∧ 1² + (m-1)*1 - m = 0
1 - m + 1 -m =0 ∧ 1+m - 1-m =0
2 - 2m = 0 ∧ 0= 0 zawsze prawdziwe ( tożsamość)
m= 1