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Δ=k²-4(k-1)=k²-4k+1>0
Δ₁=16-4=12
√Δ=2√3
m.z. k=1/2*(4-2√3)=2-√3 v k=2+√3
D: k∈(-∞, 2-√3) u (2+√3, +∞)
k-1>0
k>1
Odp. k∈(2+√3, +∞)