Dla jakich wartości parametru a równanie |x-2|=4a-1 ma dwa dodatnie pierwiastki?
|x-2|=4a-1
x - 2 = 4a - 1
x = 4a - 1 + 2
x = 4a + 1
4a + 1 > 0
4a > -1
a > -1/4
odp. a ∈ (-1/4 ; +oo)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
|x-2|=4a-1
x - 2 = 4a - 1
x = 4a - 1 + 2
x = 4a + 1
4a + 1 > 0
4a > -1
a > -1/4
odp. a ∈ (-1/4 ; +oo)