April 2019 0 24 Report
Dla jakich parametrów m poniższe równanie posiada rozwiązania?
\sin\alpha + 4m = 2m\sin\alpha + \frac{1}{2}
More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.