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ttk (4,-5)
h(x)= 2x+5
y=mx+c
gradien=m
tegak lurus -> m1.m2=-1
y=2x+5
m=2
m1.m2=-1
2.m2=-1
m2=-1/2
y-y1=m(x-x1)
y-(-5)=-1/2(x-4)
y+5=-1/2x+2
y=-1/2x+2-5
y=-1/2x-3
f(x)=-1/2x-3
pers garis yang melewati (4,-5):
y-y1 = m(x-x1)
y+5 = (-1/2)(x-4)
2y+10 = -x+4
2y = -x-6
y = -(1/2)x-3
f(x) = -(1/2)x-3