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D=4^2-4(1)(8)
D=16-32
D=-16
b² -4ac ----> discriminante
x² +4x +8 = 0
a = 1
b = 4
c = 8
b² - 4ac
(4)² -4(1) (8) =
16 - 32 = -16
Entonces como b² -4ac<0 le ecuacion tiene 2 soluciones imaginarias