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f(3+2) = f(3)+f(3-1)+2.3
f(5)=f(3)+f(2)+6 f(3)=3 - f(2)+6
f(3)= -3 - f(2)
f(1+2)=f(1)+f(0)+2 p=1
f(3)=f(1)+f(0)+2
f(1)+f(0)+2 = -3 - f(2)
f(0)+f(1)+f(2) = -3 - 2 = -5