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V₂ : V₁ = [¹/₃.π.r₂².t₂] : [¹/₃.π.r₁²]
V₂ : V₁ = [r₂².t₂] : [r₁².t₁]
Diketahui r₂ = 2.r₁ dan t₂ = 3.t₁, maka
V₂ : 40 = [(2.r₁)²(3.t₁)] : [r₁².t₁]
V₂ : 40 = [4 x 3] : 1
V₂ = 40 x 12
∴ Volum kerucut yang baru adalah 480 cm³
-selesai-