Diketahui segitiga ABC siku-siku di B. Jika cos A=¾, maka nilai cotan A adalah?? tolong bantuannya dengan caranya
subebe
Cos² A + sin² A = 1 (3/4)² + sin ² A = 1 9 / 16 + sin² A = 1 sin² A = 1 - 9/16 sin² A = 7/16 sin A = √7 / 4 Cotan A = cos A / Sin A = (3/4) / (√7/4) = 3 / √7 = 3√7 / 7
(3/4)² + sin ² A = 1
9 / 16 + sin² A = 1
sin² A = 1 - 9/16
sin² A = 7/16
sin A = √7 / 4
Cotan A = cos A / Sin A = (3/4) / (√7/4) = 3 / √7 = 3√7 / 7