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F(5)= 5a + b -----> 5a + b = 0
F(-5) = -5a + b ------> -5a + b = -30
_____________ -
10a = -30
a = -3
-5a + b = -30
-5(-3) + b = -30
15 + b =-30
b = -15
b+3a² = -15 + 3(-3²)
= -15 +( 3X9)
= -15 + 27
= 12
Jadi, nilai dari (b + 3a²) adalah 12
f(5) = 0
a.5+b = 0
5a+b = 0 ... (i)
f(-5) = -30
a.(-5)+b = -30
-5a+b = -30 ... (ii)
eliminasi (i)&(ii) :
5a+b = 0
-5a+b = -30
____________ -
10a = 30
a = 30/10
a = 3
disubstitusikan ke (i) :
5a+b = 0
5.3+b = 0
15+b = 0
b = -15
maka,
nilai b+3a²
= -15+3.3²
= -15+3.9
= -15+27
= 12