Diketahui persamaan garis g: 2x +5y +10 = 0. Tentukan persamaan garis berikut. a. garis h sejajar garis g dan melalui titik (2,3) b. garis l tegak lurus garis g dan melalui titik potong garis g dengan sumbu Y.
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G : 2x + 5y + 10 = 0 => m = -a/b = -2/5 a. h sejajar g maka m = -2/5 dan melalui (2,3) y - y1 = m(x - x1) => y - 3 = -2/5 (x - 2) => 5y - 15 = -2x + 4 => 2x + 5y - 19 = 0
b. l tegak lurus g maka m = 5/2 melalui titik potong garis g thp sb y (x = 0) 2x + 5y + 10 = 0 => 2(0) + 5y = -10 => y = -2 pers garis l bergradien m = 5/2 melalui (0,-2) y - y1 = m(x - x1) => y - (-2) = 5/2(x - 0) => y + 2 = 5/2 x => 2y + 4 = 5x => 5x - 2y - 4 = 0
a. h sejajar g maka m = -2/5 dan melalui (2,3)
y - y1 = m(x - x1)
=> y - 3 = -2/5 (x - 2)
=> 5y - 15 = -2x + 4
=> 2x + 5y - 19 = 0
b. l tegak lurus g maka m = 5/2 melalui
titik potong garis g thp sb y (x = 0)
2x + 5y + 10 = 0 => 2(0) + 5y = -10 => y = -2
pers garis l bergradien m = 5/2 melalui (0,-2)
y - y1 = m(x - x1)
=> y - (-2) = 5/2(x - 0)
=> y + 2 = 5/2 x
=> 2y + 4 = 5x
=> 5x - 2y - 4 = 0