DIKETAHUI LUAS PERMUKAAN SUATU KERUCUT 438,815 DM KUADRAT 2 .JIKA JARI JARINYA 6,5 DM, TENTUKAN LUAS SELIMUT KERUCUT TERSEBUT
permatapu3maharani
Lp = pi r ( s + r ) 438,815 = 3,14.6,5 ( s + 6,5) s + 6,5 = 438,815/20,41 s = 21,5-6,5 s = 15dm Ls = pi r s = 3,14.6,5.15 = 306,15cm^2
438,815 = 3,14.6,5 ( s + 6,5)
s + 6,5 = 438,815/20,41
s = 21,5-6,5
s = 15dm
Ls = pi r s
= 3,14.6,5.15
= 306,15cm^2