Jawab:
Trigonometri"
Luas segitiga
Penjelasan dengan langkah-langkah:
Luas Δ ABC = 3√3
1/2. AB. AC. sin A = 3√3
1/2. 6. 2 . sin A = 3√3
6. sin A = 3√3
sin A = (3√3)/(6) = 1/2 √3 = sin 60
<A = 60
..
aturan cosinus
BC² = AB²+ AC² - 2. AB. AC . cos A
BC² = 36 + 4 - 2. 6. 2 . cos 60
BC² = 36 + 4 - 24 (1/2)
BC² = 40 - 12
BC² = 28
BC = 2√7
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Verified answer
Jawab:
Trigonometri"
Luas segitiga
Penjelasan dengan langkah-langkah:
Luas Δ ABC = 3√3
1/2. AB. AC. sin A = 3√3
1/2. 6. 2 . sin A = 3√3
6. sin A = 3√3
sin A = (3√3)/(6) = 1/2 √3 = sin 60
<A = 60
..
aturan cosinus
BC² = AB²+ AC² - 2. AB. AC . cos A
BC² = 36 + 4 - 2. 6. 2 . cos 60
BC² = 36 + 4 - 24 (1/2)
BC² = 40 - 12
BC² = 28
BC = 2√7