Diketahui ²log3=x dan ²log5= y. nilai dari ⁴log45 =
tazkiaalfi
²log 3 = x dan ²log 5 = y ⁴log 45 = ²log 45 per ²log 4 = ²log (15×3) per ²log 2² = ²log 15 + ²log 3 per 2. ²log 2 = ²log (5×3) + ²log 3 per 2.1 = ²log 5 + ²log 3 + ²log 3 per 2 = y + x + x per 2 = 2x + y per 2
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arsetpopeye
4log45 = (2^2)log45 = (1/2) 2log45 = (1/2) 2log(3.3.5) = 1/2 (2log3 + 2log3 + 2log5) = 1/2 (x + x + y) = 1/2 (2x + y) Atau = (2x + y)/2 Atau = x + (1/2)y
⁴log 45 = ²log 45 per ²log 4
= ²log (15×3) per ²log 2²
= ²log 15 + ²log 3 per 2. ²log 2
= ²log (5×3) + ²log 3 per 2.1
= ²log 5 + ²log 3 + ²log 3 per 2
= y + x + x per 2
= 2x + y per 2
= (1/2) 2log(3.3.5)
= 1/2 (2log3 + 2log3 + 2log5)
= 1/2 (x + x + y)
= 1/2 (2x + y)
Atau
= (2x + y)/2
Atau
= x + (1/2)y