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Misalkan titik tengah AC adalah O, maka AO = 1/2 AC = 3 cm
tinggi limas = TO =
=
=
=
= 9 cm
b)
luas sisi tegak = 1/2 x 6 x 9
= 27
luas seluruh sisi tegak = 3 x 27 = 81
tinggi segitiga alas =
=
=
=
= 3 cm
luas alas = 1/2 x 6 x 3
= 9
Luas seluruh permukaan = 81 + 9