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AB = √3 cm
BT² = AT² + AB²
= 1² + √3²
= 1 + 3
= 4
BT = √4
= 2
solusi
jarak A ke BT = α
menggunakan rumus L.segitiga
√3 × 1 = 2 × α
√3 = 2α
α = √3/2 cm