Question

Diketahui Ksp Fe(OH)2 = 8x10^-16. Tentukanlah kelarutan Fe(OH)2 dalam akuades dan larutan NaOH 0,01 M

Answer 1

Ksp fe(oh)2 = [fe2+][2oh-]^2
= s 2s^2
= 4s^3
Naoh = na+ + oh-
0,01
Fe(Oh)2 + Naoh
ksp fe(Oh)2 = [fe2+][2oh-]^2
8.10^-16 = s (s+0,01)^2 ~~~>> s nya diabaikan karna sama yg + 0,01
8.10-16 = s (10^-2)^2
8.10^-16 = s 10^-4
s = 8.10^-16/10^-4
s = 8.10^-4
maaf klo salah yaa