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s=13
t²=s²-r²=13²-5²=169-25=144
t=√144=12 cm
V=⅓πr²t
V=⅓. 3,14. 5. 5. 12
V=314 cm³
= akar (169 -25)
= 12 cm
b. volum kerucut = 1/3 * phi * r^2 * t
= 1/3 * phi * 5^2 * 12
= 100 phi cm3