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H(-2) = 1 ⇒ 1 = - 2m + n ... (1)
H(0) = 5 ⇒ 5 = m(0) + n
n = 5
substitusi:
-2m + 5 = 1
-2m = -4
m = 2
H(x) = 2x + 5
H(-8) = 2(-8) + 5
= - 11