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f(-1) = -p + q = -5
f(4) = 4p + q = 5
eliminasi q
f(x) = -5p = -10, maka p = 2
masukan p ke salah satu persamaan
4p + q = 5
4.2 + q = 5
8 + q = 5, maka q = 5 - 8 = -3
masukan nilai p = 2 dan q = -3, ke soal
f(-6) = 2.-6 + (-3) = -12 - 3 = -15
f(4) ⇒ 4p + q = 5
⇒⇒v⇒⇒⇒⇒⇒⇒⇒⇒ -
- 5p = - 10
p = 2
subtitusi ⇒ -1p + q = - 5
-1(2) + q = -5
-2 + q = -5
q = -3
jadi nilai
f(-6) = px + q
⇒ 2 (-6) + -3
⇒ - 12 + - 3
⇒ - 15
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