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f(x) = ax + b
3 = a(1) + b
3 = a + b
f(x) = ax + b
5 = a(2) + b
5 = 2a + b
eliminaasi
3 = a + b
5 = 2a + b
-------------------------- -
-2 = -a
2 = a
3 = a + b
3 = 2 + b
3 - 2 = b
1 = b
2. f(2) = 3 dan f(4) = 4
f(x) = ax + b
3 = a(2) + b
3 = 2a + b
f(x) = ax + b
4 = a(4) + b
4 = 4a + b
eliminasi
3 = 2a + b
4 = 4a + b
------------------ -
-1 = -2a
1/2 = a
3 = 2a + b
3 = 2 . 1/2 + b
3 = 1 + b
3 - 1 = b
2 = b