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a.f(1) = 3; f(2) = 5
3 = a(1) + b 5 = a(2) + b
3 = a + b 5 = 2a + b
eleminasi
2a + b = 5
a + b = 3 --
---------------------------
a = 2
3 = a + b
3 = 2 + b
3-2 = b
b = 1
f(x) = 2x + 1
f(2) = 3 ; f(4) = 4
3 = a(2) + b 4 = a(4) + b
3 = 2a + b 4 = 4a + b
4a + b = 4
2a + b = 3
2a = 1
a = 1/2
3 = 2a + b
3 = 2(1/2) + b
3 = 1 + b
b = 3-1
b = 2
f(x) = 1/2x + 2
f(x) = ax + b
3 = a(1) + b
3 = a + b
f(x) = ax + b
5 = a(2) + b
5 = 2a + b
eliminaasi
3 = a + b
5 = 2a + b
-------------------------- -
-2 = -a
2 = a
3 = a + b
3 = 2 + b
3 - 2 = b
1 = b
2. f(2) = 3 dan f(4) = 4
f(x) = ax + b
3 = a(2) + b
3 = 2a + b
f(x) = ax + b
4 = a(4) + b
4 = 4a + b
eliminasi
3 = 2a + b
4 = 4a + b
------------------ -
-1 = -2a
1/2 = a
3 = 2a + b
3 = 2 . 1/2 + b
3 = 1 + b
3 - 1 = b
2 = b