Question

Diketahui f(a)= 2a-3 dan g(a)=1-a. tentukan a jika (f bundaran g) (a)=6.

Answer 1

DIketahui f(a) = 2a - 3, g(a) = 1 - a dan (f°g)(a) = 6
Buatlah menjadi persamaan (f°g)(a), maka:
(f°g)(a) = 6
=> f[g(a)] = 6
=> f(1 - a) -> 2a - 3 = 6
=> f(1 - a) -> 2(1-a) - 3 = 6
=> 2(1 - a) = 9
=> 2 - 2a = 9
=> -2a = 7, maka a = 

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