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Verified answer
F(x) = x² + x - 1g(x) = 2x + 1
(f o g)(x) = f[g(x)]
= (2x + 1)² + (2x + 1) - 1
= 4x² + 4x + 1 + 2x + 1 - 1
= 4x² + 6x + 1
(f o g)(x) = 4x² + 6x + 1