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U4 = U1+(4-1)b
12 = u1 +3b......1
U8= U1+(8-1)b
24= U1+7b.....2
3liminasi perz 1 dan 2
12= u1+3b
24= u1+7b
_________-
-12=-4b
b = 3
subtitusi b=3 ke prs 1
12= u1+3b
12= u1+3(3)
12= u1+9
U1= 12-9
u1= 3
u50 = u1+(n-1)b
=3+(50-1)3
=3+49x3
= 3+147
= 150