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f{h(x²+2x-3) = x² +6
h(x²+2x-3)-2 = x² +6
h(x²+2x-3)=x² +8
x²+2x-3 =5 atau menjadi x²+2x-8 =0 atau (x+4)(x-2)=0
atau x= -4 dan x =2, dipilih x=2 >0
maka
h(x²+2x-3)=x² +8
h(5)=2² +8= 4 +8=12