Question

Diket : massa 1 = 1kg
massa 2 = 2kg
F=6N
Ditanya =hitunglah gaya kontam kedua balok tersebut?

NB : di foto soal nomor 4

Answer 1

DINAMIKA

m1 = 2 kg
m2 = 2 kg
F = 6 N
lantai licin
F12 = _?

gaya kontak
F12 = m1 / (m1 + m2) • F
F12 = 1 / (1+2) • 6
F12 = 2 N ← jwb


atau
a = F / (m1 + m2) = 6 / (1+2) = 2 m/s²
F12 = m1 a = 1 • 2 = 2 N



Ok ?