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m1 = 2 kg
m2 = 2 kg
F = 6 N
lantai licin
F12 = _?
gaya kontak
F12 = m1 / (m1 + m2) • F
F12 = 1 / (1+2) • 6
F12 = 2 N ← jwb
atau
a = F / (m1 + m2) = 6 / (1+2) = 2 m/s²
F12 = m1 a = 1 • 2 = 2 N
Ok ?