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a. f(x) + g(x)
=> 2 (x+3) + 5 (3-x) = 2x + 6 + 15 - 5x = -3x + 21
b. f(x) - g(x)
=> 2 (x+3) - 5 (3-x) = 2x + 6 - 15 + 5x = 7x - 9
c. f(x) . g(x)
=> { 2 (x+3)} . {5 (3-x) } = (2x + 6) . (15-3x) = 12x - 6 + 90
d. (f + g) (2)
=> 2 (x+3) + 5 (3-x) = 2x + 6 + 15 - 5x = -3x + 21 = -3 (2) + 21 =- 6 + 21 = 15
e. (f - g) (3)
=> 2 (x+3) - 5 (3-x) = 2x + 6 - 15 + 5x = 7x - 9 = 7 (3) - 9 = 21 - 9 = 12
f. (f . g) (-3)
=> { 2 (x+3)} . {5 (3-x) } = (2x + 6) . (15-3x) = 12x - 6 + 90
= 12 (-3) - 6 + 90
= -36 - 6. 9 + 90
= - 42 + 90
= 48