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=f(2x+1) = 1+ (2x+1)²
=1+ 4x²+4x+1= 4x²+4x+2
b) gof = g(f(x)) =g(1-x²)
=2(1-x²)+1 = 2-2x²+1= 3-2x²
c) f(f(x)) =1-(1-x²)= -2+x²
d)g(g(x))= 2(2x+1)+2 = 4x+2+2
=4x+4