Diketahui:
f(x) = √x-1
(fog)(x) = 3√x+1
Ditanyakan:
g(x)
Jawab:
(fog)(x) = f(g(x))
3√x+1 = √g(x)-1
3√x+2 = √g(x)
(3√x+2)² = g(x)
9x+12√x+4 = g(x)
Mapel: Matematika
Kelas: 10
Materi: Komposisi Fungsi
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Diketahui:
f(x) = √x-1
(fog)(x) = 3√x+1
Ditanyakan:
g(x)
Jawab:
(fog)(x) = f(g(x))
3√x+1 = √g(x)-1
3√x+2 = √g(x)
(3√x+2)² = g(x)
9x+12√x+4 = g(x)
Mapel: Matematika
Kelas: 10
Materi: Komposisi Fungsi