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ZnCl₂ --> Zn²⁺ + 2Cl⁻
w = eit/96500
w = eF
Zn : Reduksi - Katoda
w = 65/2 x 0,2
w = 6,5 gram
Cl : Oksidasi - Anoda
2Cl⁻ --> Cl₂ + 2e⁻
Cl⁻ ~ e⁻ = 0,2 mol
V Cl₂ = 0,2 x 22,4 = 4,48 L
∴Jawaban : B. Endapan Zn 6,5 gram