" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Pendiente: m=(y2-y1)/(x2-x1)
m=(y-(-3))/(8-(-4))=(5-(-4))/(3-4),
(y+3)/(8+4)=(5+4)/(3-4), (y+3)/(12)=(9)/(-1), (y+3)/(12)=-9,
(y+3)=12(-9), y=12(-9)-3=-111
y=-111
Formula dos puntos de la recta:
y=((y2-y1)/(x2-x1))(x-x1)+y1
Sea (x1, y1) = (-4,-3), (x2, y2) = (8, Y) = (8, -111), entonces:
y = ((y2-y1)/(x2-x1))(x-x1)+y1 = ((-111-(-3))/(8-(-4)))(x-(-4))+(-3)
= (-118/12)(x+4)-3 = -9(x+4)-3 = -9x-36-3 = -9x-39 = -3(3x+13)
Por lo tanto, la ecuación de la recta que es paralela a la recta que
pasa por (4,-4) y (3,5) es:
y = -3(3x+13)