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Si "x" es el primer natural, "x+1" será el segundo y "x+2" el tercero, luego
x/2 + 2/3 * (x+1) = x + 2
1/2 x + 2/3 x + 2/3 = x + 2
7/6 x = x + 2 - 2/3
7/6 x = x + 4/3
7/6 x - x = 4/3
1/6 x = 4/3
x = 4/3 ÷ 1/6
x = 8
R/ Los números son 8, 9 y 10.
Prueba:
La mitad del primero = 4, dos tercios del segundo = 6, y 4 + 6 = 10