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X+1 =?
X+2 =?
La mitad del menor = x/2
Tercera parte de mayor = (X+2)/3(el mayor es X+2)
X/2 + (x+2)/3 = 19 (1)
[3×X + 2(X+2)]/6 =19
3X + 2X +4 = 19 ×6
5X +4 = 114
5X = 114 - 4
5X = 110
X= 110/5
X = 22
Verificamos en (1)
X/2 + (x+2)/3 = 19
22/2 + (22+2)/3
11+ (24/3)=
11 + 8 = 19
cual es el numero del medio?
X +1 => 22+1 = 23
R. Es 23