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9 =( a+4b)-(a+b)
= 3b
maka b=9/3 = 3
U3+U4 = a+2b+a+3b
29 = 2a + 5b
29=2a+(5.3)
=2a+15
maka 2a=29-15 = 14
maka a=14/2=7
maka diketahui a=7, b=3
Un=a+(n-1)b
U10=7+(10-1)3
U10=7+(9.3)
U10=7+27
U10=34(d)
U3+U4 = 29
⇒ (U1+4b) - (U1+b) = 9
(U1+2b) + (U1+3b) = 29
5b = 9
2U1 + 5b = 29
-2U1 = -20
U1 = 10
⇒ Substitusi;
2U1 + 5b = 29
2.10 + 5b = 29
20 +5b = 29
5b = 9
b = 1,8
⇔U10 = U1 + 9b
= 10 + 9.1,8
= 10 + 16,2
= 26,2