Dany jest ciag an=n do potegi 2-3n, wyraz an+1 ma postac..?
an = n² - 3n
a(n+1) = (n+1)² - 3(n+1) = n² + 2n + 1 - 3n - 3 = n² -n - 2
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an = n² - 3n
a(n+1) = (n+1)² - 3(n+1) = n² + 2n + 1 - 3n - 3 = n² -n - 2
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)