dane sa punkty ktore leza na prostej A=(2;-1) ,B=(-3;4), napisz rownanie tej prostej
(y+1)(-3-2)-(4+1)(x-2)=0
-3y-2y-3-2-(4x-8+x-2)=0
-3y-2y-3-2-4x+8-x+2=0
-5y-5=5x-10/:5
-y-1=x-2
-y=x-2+1
-y=x-1/*(-1)
y=x+1
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(y+1)(-3-2)-(4+1)(x-2)=0
-3y-2y-3-2-(4x-8+x-2)=0
-3y-2y-3-2-4x+8-x+2=0
-5y-5=5x-10/:5
-y-1=x-2
-y=x-2+1
-y=x-1/*(-1)
y=x+1