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log_a (b) = c <=> a^c=b
log_2 (8) = c <=> 2^c=8
2^c=2^3
c=3 = log_a (8)
log_4 (16) = 2
log_10 (100) = 2
Stąd wyrażenie wygląda tak: 3 - 3*2 + 2*3 = 3 - 6 + 6 = 3