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64 = 512 . r^3
64/512 = r^3
1/8 = r^3
r = 1/2
Rumus umum deret geometri utk r < 1
Sn = a(1-r^n) / 1-r
= 512 ( 1 - 1/2^7) / 1/2
= 512 ( 1-1/128) x 2/1
= 512 x 127/128 x 2
= 1016 ( B )
Maka, jumlah 7 suku pertama :