Vstp = 224 ml = 0,224 liter
Reaksi di Anoda
2 H2O ==> O2 + 4 H+ + 4e
Arus yg mengalir => Faraday (F)
F = Vstp x elektron/22,4
= 0,224 x 4/22,4
= 0,04 F
Reaksi di katoda
Cu^2+ + 2e ==> Cu
e Cu = Ar/elektron
= 63,5/2
= 31,75
W = e x F
= 31,75x 0,04
= 1,27 gram
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Vstp = 224 ml = 0,224 liter
Reaksi di Anoda
2 H2O ==> O2 + 4 H+ + 4e
Arus yg mengalir => Faraday (F)
F = Vstp x elektron/22,4
= 0,224 x 4/22,4
= 0,04 F
Reaksi di katoda
Cu^2+ + 2e ==> Cu
e Cu = Ar/elektron
= 63,5/2
= 31,75
W = e x F
= 31,75x 0,04
= 1,27 gram