daje naj ;)
(x³-3x²)/(x²-6x+9)
Δ=b²-4ac=36-36=0
x⁰=-b/2a=6/2=3
D=R/3
x²(x-3)/(x-3)²=x²/(x-3)
2]
(x²+4)/(x³+8x²+16x)
x³+8x²+16x=x(x²+8x+16)≠0
Δ=64-64=0
x₀=-8/2=-4
D=R/[0;-4]
(x²+4)/[x(x+4)²]
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(x³-3x²)/(x²-6x+9)
Δ=b²-4ac=36-36=0
x⁰=-b/2a=6/2=3
D=R/3
x²(x-3)/(x-3)²=x²/(x-3)
2]
(x²+4)/(x³+8x²+16x)
x³+8x²+16x=x(x²+8x+16)≠0
Δ=64-64=0
x₀=-8/2=-4
D=R/[0;-4]
(x²+4)/[x(x+4)²]