Czy umiecie to rozwiązać?
(5-2x)²-11
(3x-8)(x-4)- ------------ >2(x+5)²-(x-√5)(x+√5)
2
(5-2x) ²-11= 25-20x+4x²-11=24-20x+4x²
(3x-8)(x-4)=2(x+5)²-(x-√5)(x+√5)
3x²-12x-8x+32=2*(x²+10x+25)-x²-5
3x²-16x+32=2x²+20x+50+x²+5
-36x=23/(-36)
x=-23/36
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(5-2x) ²-11= 25-20x+4x²-11=24-20x+4x²
(3x-8)(x-4)=2(x+5)²-(x-√5)(x+√5)
3x²-12x-8x+32=2*(x²+10x+25)-x²-5
3x²-16x+32=2x²+20x+50+x²+5
-36x=23/(-36)
x=-23/36