Czy sin^2 x = sin^2 -x
L = sin²x = sinx·sinx
P = sin²(-x) = sin(-x)·sin(-x) = (-sinx)·(-sinx) = sinx·sinx
L=P
Czyli sin²x = sin²(-x)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
L = sin²x = sinx·sinx
P = sin²(-x) = sin(-x)·sin(-x) = (-sinx)·(-sinx) = sinx·sinx
L=P
Czyli sin²x = sin²(-x)