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y- ilość monet 5-groszowych
x=y=30
2x+5y=100
b - liczba monet 5gr
a + b = 30 I× (-2)
2a + 5b = 100
-2a -2b = -60
2a + 5b = 100
.................
3b = 40 I : 3
2a + 5b = 100
b = 13 1/3
2a + 5b = 100
Odp. Nie, z racji ze nie można dać 13 i 1/3 monety