Cześć. Bardzo proszę o rozwiązanie zadania.
a)
b)
c)
d)
e)
f) ^{2}
(2a -1 )² = (2a)² - 2*2a*1 + 1² = 4a² - 4a+1
(-3x + 1)²=(-3x)² + 2*(-3x)*1+1² = 9x² - 6x + 1
(-3-x)² = (-3)²+2*(-3)*(-x)+(-x)² = 9 + 6x + x²
(3a - 1)³=(3a)³ - 3*(3a)²*1 + 3*3a*1² -1³ = 27a³ - 27a² + 9a -1
(2+x)³ = 2³ + 3*2²*x + 3*2*x² + x³ = 8 + 12x + 6x²+x³
f)
x³ - 27 = x³ - 3³ = (x-3)(x² + 3x + 9)
wzory:
(a+b)²=a²+2ab+b²
(a-b)² = a²-2ab+b²
(a+b)³ = a³+3a²b + 3ab² + b³
(a-b)³ = a³- 3a²b + 3ab² -b³
a³ -b³ = (a-b)(a²+ab+b²)
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a)
(2a -1 )² = (2a)² - 2*2a*1 + 1² = 4a² - 4a+1
b)
(-3x + 1)²=(-3x)² + 2*(-3x)*1+1² = 9x² - 6x + 1
c)
(-3-x)² = (-3)²+2*(-3)*(-x)+(-x)² = 9 + 6x + x²
d)
(3a - 1)³=(3a)³ - 3*(3a)²*1 + 3*3a*1² -1³ = 27a³ - 27a² + 9a -1
e)
(2+x)³ = 2³ + 3*2²*x + 3*2*x² + x³ = 8 + 12x + 6x²+x³
f)
x³ - 27 = x³ - 3³ = (x-3)(x² + 3x + 9)
wzory:
(a+b)²=a²+2ab+b²
(a-b)² = a²-2ab+b²
(a+b)³ = a³+3a²b + 3ab² + b³
(a-b)³ = a³- 3a²b + 3ab² -b³
a³ -b³ = (a-b)(a²+ab+b²)