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1 mol Pb(NO₃)₂ = 331,2 g Pb(NO₃)₂
1mol Pb(NO₃)₂ = 6 mol O
1 mol O = 6,02 ×10²³ atomos O
91,5 g Pb(NO₃)₂ × 1 mol Pb(NO₃)₂ × 6 mol O × 6,02 ×10²³ atomos O⇒
331,2 g Pb(NO₃)₂ × 1mol Pb(NO₃)₂ × 1 mol O
3,305×10²⁶ atomos O = 9,98×10²³ atomos O
331,2