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3(x²+4x) = 0
x² + 4x = 0
x(x+4) = 0
x+4 = 0
x = -4
3x(x² + 4) =0
3x = 0
x = 0/3
x = 0 primera raiz
x² +4 = 0
x² = -4 tiene 2 raices imaginarias
x = √-4
x = √4(-1)
x = √4 *√-1
x = 2√-1 como √-1 0 i reemplazamos
x = 2i
x= -√-4
x= -√(4)(-1)
x = -2√-1
x = -2i
Soluciones
x = 0
x = -2i
x = 2i